Particle velocity and acceleration in dynamics

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frank1234
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I need help with my dynamics homework. This is what I have so far, I hope you can read my writing (let me know if something is unclear). Can someone help me with how to approach this problem and where to go next? Thank you!
HW013.jpg
 

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Periphery of inner wheel and hence that of outer has tangential speed equal to 180t.now at t as found by you 0.38.
so v at the end of 0.38 sec equals 68.4(Pl. make corrections in your solution.)
Now tangential acc.=dv/dt=180
Normal acc.=-v^2/R3=-68.4/105=0.65
Resultant acc. at end of 0.38 sec=sqrrt(0.65^2+180^2)=180 approx.