Particular Integral of Exponential

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SUMMARY

The discussion focuses on solving a first-order linear system transient response for a temperature sensor with a time constant (τ) of 18 seconds. The governing equation is presented as τ dy(t)/dt + y(t) = K, where K is defined as 5 + t/3. The solution involves determining the total temperature response, T(total), which is the sum of the homogeneous solution, T(homogenous) = Ae^(-t/5), and the particular integral, T(particular-integral). The user seeks assistance specifically with calculating the particular integral to find the constant A using the initial condition T(0) = 5V.

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  • Understanding of first-order linear differential equations
  • Familiarity with transient response analysis
  • Knowledge of initial value problems in ordinary differential equations (ODEs)
  • Basic calculus, specifically integration techniques
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  • Study the method of integrating factors for first-order linear differential equations
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  • Explore the concept of homogeneous and particular solutions in differential equations
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Students and professionals in engineering, particularly those studying control systems or thermal dynamics, will benefit from this discussion. It is also relevant for anyone working with first-order linear systems and transient response analysis.

madman01
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First-Order Linear System Transient Response

Hey there,

I am trying to solve a problem of first order equation which is

A temperature sensor has a first order response with τ = 18 seconds. The calibration curve of the sensor is presented in Figure 1. Graph the sensor response when it is exposed to the temperature profile shown in Figure 2. Present the senor voltage as a function of time. Sensor has been kept at 15 °C for a long time before the operation.

Homework Statement



\taudy(t)/dt + y(t) = K
Figure 1 & 2 are attached

Homework Equations



where \tau =18 and K is given by an equation 5+t/3 (deduce from figure 1)

The Attempt at a Solution



I know that first order equation’s answer is the addition of two general solutions: homogenous (natural response of the equation) and particular-integral (generated by the step function there

T(total) = T(homogenous) + T(particular-integral)
T(homogenous)= Ae^-t/5
T(particular-integral)= I am not sure how to do the integral of Ae^-t/5 ... Any Idea's

So if someone can help me with the T(particular-integral) then i would be able to find the value of A by putting the initial condition of T(0)=5V
 

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  • Figure 1 & 2.jpg
    Figure 1 & 2.jpg
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Last edited:
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You could assume that a particular solution is at + b. Substitute this into the equation and solve for a and b.
 
Hint: divide both sides by tau. If you have studied ODE's, this hint should be enough.
 
Last edited:

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