- #1

MathematicalPhysicist

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and how could you solve for m number of numbers to the power n?

(a+b+c+...+d)^n

||

\/

m numbers.

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- Thread starter MathematicalPhysicist
- Start date

- #1

MathematicalPhysicist

Gold Member

- 4,699

- 369

and how could you solve for m number of numbers to the power n?

(a+b+c+...+d)^n

||

\/

m numbers.

- #2

HallsofIvy

Science Advisor

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What you need are "multinomial" coefficients.

The binomial coefficients are given by

The "trinomial" coefficient for x

If you have "m" numbers to the "n" power: (x

(i+ j+ ...+ k)!/(i! j! ... k!).

- #3

MathematicalPhysicist

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thanks

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