Pathlength Difference from two waves

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SUMMARY

The discussion centers on calculating the pathlength difference between two waves originating from slits separated by 0.12 mm, illuminated by a coherent light source with a wavelength of 549E-6 mm. The pathlength difference at the first maximum (m=1) is determined using the equation d*sin(theta) = m*wavelength, where the distance to the screen (D) is 780 mm. The participant successfully calculated the distance between the two maxima (y) as 0.0036 m and concluded that the pathlength difference is directly related to the order of the maximum (m) multiplied by the wavelength.

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Homework Statement


Two slits separated by a distance of d = 0.12mm are located at a distance of D = 780mm from a screen. The screen is oriented parallel to the plane of the slits. The slits are illuminated by a coherent light source with a wavelength of lambda = 549E-6 mm. The interference pattern shows a peak at the center of the screen (m=0) and then alternating minima and maxima.
7. [1pt]
What is the pathlength difference between the two waves from the two slits at the first (m=1) maximum on the screen?

Homework Equations


d*sintheta = m*wavelength
sintheta = y(dist bt two maxima) / D(distance to screen)


The Attempt at a Solution


I'm really confused about what the "pathlength difference" refers to. It doesn't specify it in the book. I know the angles take different paths to get to the same point because of the distance inbetween them, but is it asking for an angle?
I solved the problem for y using the above equations, and at the first maxima (m=1), y(distance between the two maxima) is 0.0036m. But I don't know where to go from there?
 
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So...I think I just realized that pathlength difference refers to "m", but what are the units??
 
Ah, just figured it out...you have to use "m" and multiply it by the wavelength.
 

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