Patterns found in complex numbers

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SUMMARY

This discussion focuses on solving the equation zn = i using De Moivre's Theorem for n = 3, 4, and 5. The correct solutions for z3 = i are identified as z = cis(π/6), cis(π/6 + 2π/3), and cis(π/6 + 4π/3), which correspond to the complex numbers √3/2 + 0.5i, -√3/2 + 0.5i, and -√3/2 - 0.5i. A mistake was noted in the third solution, which should be -i instead. The discussion also touches on generalizing solutions for zn = 1 + bi, particularly when |a + bi| = 1 and when |a + bi| ≠ 1.

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  • Familiarity with polar and rectangular forms of complex numbers
  • Knowledge of complex number modulus and argument
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lll030lll
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Patterns found in complex numbers URGENT!

  • use de moivre's theorem to obtain solutions to z^n = i for n=3, 4, 5
  • generalise and prove your results for z^n = 1+bi, where |a+bi|=1
  • what happens when |a+bi|≠1?

Relevant equations[/b]
r = √a^2 + b^2
z^n = r^n cis (nθ)


This is what i have done:
z^3=i
z^3=i cis(0)
z^3=cis(π/2+2kπ),k=0,1,2
z=cis(π/6+2kπ/3),k=0,1,2
z=cis(π/6),cis(π/6+2π/3),cis(π/6+4π/3)
z=√3/2+0.5i,-√3/2+0.5i,- √3/2-0.5i

but the 3rd solution is incorrect, should be -i. what have i done wrong?
 
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welcome to pf!

hi lll030lll! welcome to pf! :smile:
lll030lll said:
z=cis(π/6+2kπ/3),k=0,1,2
z=cis(π/6),cis(π/6+2π/3),cis(π/6+4π/3)
z=√3/2+0.5i,-√3/2+0.5i,- √3/2-0.5i

but the 3rd solution is incorrect, should be -i. what have i done wrong?

dunno, but π/6+4π/3 = 9π/6 :redface:

(personally, i find degrees easier … 30°, 30° ± 120° :wink:)
 


anyway, got it right in using a+bi=re^iθ
 

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