PDE i.v.p. using method of characteristics

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The discussion focuses on solving the partial differential equation x²uₓ + y²uᵧ = 0 with the initial condition u(2,y) = y. The method of characteristics is employed, leading to the relationship y' = (y/x)², which is solved using separation of variables. The solution involves expressing u(x,y) as a function of C, where C = (y-x)/(xy). The user struggles with determining the function f based on the initial condition and seeks clarification on this step. Ultimately, they successfully find an alternative solution through a system of ordinary differential equations and a coordinate transformation but still desire insight into the original method.
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Homework Statement


solve x2ux + y2uy = 0 for u(2,y) = y

Homework Equations


The Attempt at a Solution



with a = x2 and b = y2

y' = b/a = (y/x)2 this can be solved for y by separation of variables:

y = \frac{x}{1-xC}
and
C = \frac{y-x}{xy}

now

u(x,y) = f(C) = f(\frac{y-x}{xy})

applying initial value conditions

u(2,y) = f(\frac{y-2}{2y})

this is where my understanding runs out. how do i determine f according to the initial value? i have looked at several books but they just assume this step is obvious
 
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have solved it now :smile: by taking a different approach and by converting to a system of ODEs and doing a coordinate transform from x(t) -> x(t,s) but I would still like to know how to solve it according to my original question, thanks
 
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