PDE Linear Equation Q: Homogeneous vs Nonhomogeneous

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Miike012
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My questions concerns the information in the document.
I highlighted the portion that is confusing me and a sample problem at the bottom.

Question:
Look at the equation 2.2.4 in the document.
When I set the function u equal to zero the equation becomes
0 = 0 + 0 + f(x,t) or f(x,t) = 0.

Now if you look in the document once more at the underlined green section is says that if f is equal to zero then the equation is homogeneous. However if you read the underlined orange section it says equation 2.2.4 is a nonhomogeneous equation...

This seems a bit contradictory. Some one please help me understand what they are saying.
 
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  • Textbook page on linear operators: a boxed definition L(c1u1 + c2u2) = c1L(u1) + c2L(u2), then text on testing homogeneity by setting u identically zero, with f = 0 highlighted and the PDE du/dt = k d2u/dx2 + alpha(x,t)u + f(x,t) shown below.
    PDE.jpg
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You have shown that L(0) = f(x,t). Since that isn't zero, the equation is non-homogeneous. If that f(x,t) hadn't been in the equation, you would have gotten L(0)=0 and the equation would have been homogeneous.