Peak amplitudes of E and H fields (Poynting Vector)

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Homework Help Overview

The discussion revolves around determining the peak amplitudes of the electric (E) and magnetic (H) fields associated with sunlight's intensity on the moon, specifically focusing on the relationship between these fields and the Poynting vector.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between intensity and the peak amplitudes of the E and H fields, with one participant attempting calculations based on given formulas. Questions arise about the transition from magnetic field B to magnetic field H.

Discussion Status

Participants have engaged in calculations to derive the peak amplitude of the E field and have successfully computed the H field using a basic formula. There is acknowledgment of the assumptions made regarding the nature of the power emitter.

Contextual Notes

The problem assumes a monochromatic power emitter, which influences the calculations and interpretations of the fields involved.

equation3

Homework Statement


What are the associated peak amplitudes of the E and H fields if sunlight has a maximum intensity of 1400 W/m2 on the earth’s moon?

Homework Equations


I = <s> = 1/2 c ε0E2

The Attempt at a Solution


I = <s> = 1/2 c ε0E02

1400 = (1/2)(3*108)(8.85*10-12)(E02)

1400 / (1.328*10-3) = E02 = 1.05422 * 106

E0 = √ (1.05422 * 106) = 1026.75 V/m

So the peak amplitude of the E field = E0 = 1026.75 V/m. I'm not sure how to find the H field though.

B = E0 / c = 3.42 * 106 T

I'm not really sure how to get from B to H though.
 
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equation3 said:
I'm not really sure how to get from B to H though.
It is a very basic formula: B=μH
 
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Ahhh! Thank you @ehild :)

H = B0/μ = 3.42 * 106 / 1.26 * 10-6 = 2.72155 A/m
 
Got the same results. But the problem assumes a monochromatic power emitter so the computation is for that equivalent scenario.
 

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