Pendulum conservation of energy question

1. Jun 13, 2009

1. The problem statement, all variables and given/known data
To make a pendulum, a 300g ball is attached to one end of a string that has a length of 1.4m and negligible mass. (The other end of the string is fixed) The ball is pulled to one side until the string makes a 30 degree angle with the vertical, then (with the string taut) the ball is released from rest. Find a) the speed of the ball when the string makes a 20 degree angle with the vertical and b) the maximum speed of the ball. c) What is the angle between the string and the vertical when the speed of the ball is one-third is maximum value?

m=0.300kg
length=1.4m
angle=30 degrees with vertical
vinitial=0 m/s

2. Relevant equations
ETinitial=mgh
ETfinal=0.5mv^2 + mgh
ETinitial = ETfinal

3. The attempt at a solution
a) I tried using cos20=adj/hyp and isolated adj, and subtracted adj from 1.4 to figure out the distance from the floor to the bottom of the mass on the string. I then tried substituting that answer into the equation above and tried to isolate final velocity without much success. (The answer should be 1.42m/s)

b) I tried doing the same thing as a, except that ETfinal would not have mgh because it would be at its terminal velocity when h=0. The answer should be 1.92 m/s

c) I tried solving this by multiplying all the terms with speed by 1/3, but it requires knowledge gained from the above two questions to be solved. The answer should be 29.5 degrees

Thanks.
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

2. Jun 13, 2009

rock.freak667

Here is how we start.
We will take the lowest point of the path of pendulum to 0 potential energy (our reference line). (we will call the fixed point O)

Draw the pendulum at 30 degrees. From the pendulum draw a horizontal line to meet a line from O to the lowest point (where the lines meet, we will call A). The distance from O to the lowest point is 1.4m and the distance from O to the pendulum is also 1.4m.
Can you find the length OA?

EDIT: since you are offline and won't probably be online when I am again I will continue the explanation.

When you get the distance OA, you can find the Total energy at the initial position with mgh.

Now re-draw the diagram with 20 degrees and similarly find the perpendicular distance from the line through the lowest point in the path of the pendulum. You can now get the potential energy at this distance (at this angle of 20 degrees).

So the potential energy at 20 degrees + kinetic energy at 20 degrees=Total energy of pendulum.

You should now be able to get out part a)

For part b) conservation of energy says that

Total Energy = potential energy + kinetic energy and the values of potential and kinetic increase/decrease along the the path of the pendulum, at which point will all the energy be entirely kinetic?

Part c) When you find vmax, use a little backwards logic with part a)

Last edited: Jun 13, 2009
3. Jun 13, 2009

1.4 - 1.21 = 0.19m off the ground

1.4 - 1.32 = 0.08m off the ground

mgh = 0.5mv2 + mgh
gh = 0.5v2 + gh
9.8(0.19) - 9.8(0.08) = 0.5v2
1.47 m/s = v

Although it's close, it's about 0.05 m/s off from the answer. D:

4. Jun 13, 2009

method_man

Complete Solution Removed

Hootenanny

Last edited by a moderator: Jun 13, 2009
5. Jun 13, 2009