Pendulum in a Car: Solving Homework Statement

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SUMMARY

The discussion focuses on solving a physics homework problem involving a pendulum suspended in a car traveling on a level road. The pendulum has a mass of 1.0 kg and makes a 10-degree angle with the vertical. The key equations derived include Tcos(10°) = mg for vertical forces and Tsin(10°) = ma for horizontal forces, leading to the conclusion that the car's acceleration can be calculated using the relationship a = g * tan(10°), where g is the acceleration due to gravity.

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Homework Statement


A pendulum of mass 1.0 kg is suspended from the roof of a car traveling on a level road. An observer in the car notices that the pendulum string makes an angle of 10 deg with the vertical. What is the acceleration of the car?


Homework Equations



Fc=mv^2/r

The Attempt at a Solution


I drew the FBD diagram (attached) and I wrote the vertical and horizontal force equations:
Vertically: Tcos 10 deg=mg
Horizontally: Fc=mv^2/r=Tsin10deg.
So I got he equation mgtan10deg=mv^2/r after putting the equations together. But I don't know the radius of the pendulum, so I don't know how to solve the problem.

Thanks!

Pendulum Problem.jpg
 
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Why do you use the centripetal force? Does anything move along a circle? ehild
 
The suspended mass accelerates together with the car. Some force has to exert the force needed. It can be only the tension in the string, if it makes an angle with the vertical. The horizontal component of the tension is equal to ma (a is the common acceleration of the car and the pendulum) and the vertical component is equal and opposite to gravity, mg.
 
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Oh i got it! Are the equations:
Tcos10=mg
Tsin10=ma

Sub T=mg/cos10 into Tsin10=ma, cancel out the m's and solve for a?

Actually,it gives you mass in the problem, so I don't know if I should cancel it out or not :S
 
As you get the a single equation for a from those two, the mass cancels by itself, but if you like to multiply and divide by m and making rounding errors, just do it:-p

ehild
 
I see, thanks :D
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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