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James Ray
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Member advised to type out equations and not to use images only of handwritten scratchwork
The radius seems very small (a factor of 10 less than Earth's radius. But I can't see any mistake in the solution.James Ray said:Homework Statement
View attachment 100919
Homework Equations
The Attempt at a Solution
View attachment 100920
I forgot to square the radius in the first calculation.ehild said:Your result is wrong. You should use the template and type in your work.
Now I get 11200 km.James Ray said:I forgot to square the radius in the first calculation.
The period of a pendulum is directly proportional to the square root of the length of the pendulum and inversely proportional to the square root of the acceleration due to gravity. Therefore, on a planet with a larger radius, the period of a pendulum would be longer due to a weaker gravitational pull.
No, the mass of the pendulum does not affect its period on different planets. The period of a pendulum is only dependent on the length and acceleration due to gravity.
The period of a pendulum is shorter on a planet with a stronger gravitational pull, such as Earth, compared to a planet with a weaker gravitational pull. This is because the acceleration due to gravity affects the swinging motion of the pendulum.
Yes, the length of a pendulum can be adjusted to compensate for the difference in periods on different planets. By increasing the length of the pendulum on a planet with a weaker gravitational pull, the period can be made longer to match the period on a planet with a stronger gravitational pull.
Yes, the formula for calculating the period of a pendulum is T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity. This formula can be used to calculate the period on different planets by using the appropriate values for length and acceleration due to gravity on that planet.