- #1
suspenc3
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a small mass of 0.75kg is attached to one end of a 1.25m long massless rod, and the other end is hung from a pivot. When the resulting pendulum is 30degrees from the vertical what is the magnitude of the torque about the pivot?
what i did:
-Fsin30 -mg = 0
Fsin30 = -mg
F = -14.7N
t = rFsin30
t = 1.25(-14.7sin30)
t = -9.2N
the answer is supose to be half of this what did i do wrong?
what i did:
-Fsin30 -mg = 0
Fsin30 = -mg
F = -14.7N
t = rFsin30
t = 1.25(-14.7sin30)
t = -9.2N
the answer is supose to be half of this what did i do wrong?