How Does a Pendulum Swing Conserve Momentum?

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    Pendulum Swing
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The discussion revolves around the conservation of momentum in the context of a swinging pendulum, specifically examining whether it demonstrates angular momentum, linear momentum, or both. Participants explore the dynamics involved in the pendulum's motion and the implications for momentum conservation.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the nature of momentum in a pendulum swing, questioning whether it possesses linear and angular momentum simultaneously. They explore the relationship between the pendulum's position and its momentum at different points in the swing.

Discussion Status

The conversation is ongoing, with participants offering various interpretations of momentum conservation. Some have provided reasoning regarding the conditions at the top and bottom of the swing, while others seek clarification on the definitions and implications of momentum in this context.

Contextual Notes

There is a focus on the definitions of linear and angular momentum, as well as the conditions under which they may or may not be conserved. Participants express uncertainty about their understanding of these concepts and the implications for the pendulum's motion.

Kaxa2000
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Does a pendulum swing demonstrate angular momentum, linear, both, or neither?
 
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What do you think it is and why?
 
I believe its both because during the swing the bob has a linear momentum vector with the swing. This creates an angular momentum vector out of the plane of the pendulum swing. Once it reaches its max height during the swing the force of gravity causes it to fall back the other way creating a torque vector perpendicular to plane of swing.

I'm not sure if this is completely right...I ask for confirmation
 
Kaxa2000 said:
I believe its both because during the swing the bob has a linear momentum vector with the swing. This creates an angular momentum vector out of the plane of the pendulum swing. Once it reaches its max height during the swing the force of gravity causes it to fall back the other way creating a torque vector perpendicular to plane of swing.

I'm not sure if this is completely right...I ask for confirmation

then yes, it has both linear and angular momentum.
 
Is that the same thing as saying a pendulum swing conserves angular and linear momentum??
 
Let's see. At the top of the pendulum's swing (when v=0), what's the linear & angular momentum of the bob? At the bottom of the swing, what's the linear & angular momentum of the bob? Are the two the same?
 
No

Angular momentum : L = r x p

At top of swing when v = 0

p = 0
&
L = rAt bottom of swing
p = mv

L = r x p

So they are not conserved??
 
Last edited:
Well, angular momentum at the top of the swing is actually 0 because p=0 and L=r x p. The conclusion is correct, however: neither is conserved.
 
Kaxa2000 said:
No

Angular momentum : L = r x p

At top of swing when v = 0

p = 0
&
L = r


At bottom of swing
p = mv

L = r x p

So they are not conserved??

Your question asked whether it has angular momentum and/or linear momentum, not whether it was conserved or not.
 
  • #10
x is the cross product in this case.

Is r cross product 0 = 0?

Sorry I kind of forgot cross product ...so I'm not surerockfreak, sorry maybe I shouldve restated it in the actual post but the topic title is "pendulum swing conserves what?"
 
  • #11
How does it show that neither are conserved? Is it because the result is not the same at the top of the swing and the bottom of the swing in both cases?
 

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