Kaxa2000
- 71
- 0
Does a pendulum swing demonstrate angular momentum, linear, both, or neither?
The discussion revolves around the conservation of momentum in the context of a swinging pendulum, specifically examining whether it demonstrates angular momentum, linear momentum, or both. Participants explore the dynamics involved in the pendulum's motion and the implications for momentum conservation.
The conversation is ongoing, with participants offering various interpretations of momentum conservation. Some have provided reasoning regarding the conditions at the top and bottom of the swing, while others seek clarification on the definitions and implications of momentum in this context.
There is a focus on the definitions of linear and angular momentum, as well as the conditions under which they may or may not be conserved. Participants express uncertainty about their understanding of these concepts and the implications for the pendulum's motion.
Kaxa2000 said:I believe its both because during the swing the bob has a linear momentum vector with the swing. This creates an angular momentum vector out of the plane of the pendulum swing. Once it reaches its max height during the swing the force of gravity causes it to fall back the other way creating a torque vector perpendicular to plane of swing.
I'm not sure if this is completely right...I ask for confirmation
Kaxa2000 said:No
Angular momentum : L = r x p
At top of swing when v = 0
p = 0
&
L = r
At bottom of swing
p = mv
L = r x p
So they are not conserved??