Penguin sliding up a ramp with friction

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SUMMARY

The discussion focuses on calculating the forces acting on a penguin sliding up a ramp with friction. Key variables include the weight of the penguin (W), incline angle (θ), coefficients of static (μs) and kinetic friction (μk), and the minimum (Fmin) and maximum (Fmax) forces. Participants emphasize the importance of expressing equations in symbolic form rather than substituting numerical values prematurely, which aids in troubleshooting and understanding the problem holistically. The final calculated answers for the forces are a.) 8.6N, b.) 46.2N, and c.) 38.6N.

PREREQUISITES
  • Understanding of basic physics concepts, particularly forces and friction.
  • Familiarity with free-body diagrams and their application in problem-solving.
  • Knowledge of algebra for manipulating equations and performing dimensional analysis.
  • Experience with using spreadsheets for calculations and error checking.
NEXT STEPS
  • Study the principles of static and kinetic friction in detail.
  • Learn how to create and interpret free-body diagrams for various scenarios.
  • Explore dimensional analysis techniques to verify the correctness of equations.
  • Practice using spreadsheet software for solving physics problems and performing calculations.
USEFUL FOR

Students in physics courses, educators teaching mechanics, and anyone interested in understanding the dynamics of objects on inclined planes with friction.

isukatphysics69
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1. Homework Statement

in picture
IMG_20180326_214212.jpg


Homework Equations

The Attempt at a Solution


in picture, not sure if i am even doing this properly but i think i am? i am going to continue trying part b but please if you can let me know if i am doing this proper let me know...Thank you
 

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Your work so far is probably OK but it is hard to follow what you are doing because you are substituting numbers right from the start. It is best to find an expression in terms of symbols giving the minimum force in part (a) in terms of symbols not numbers. Use W = weight of penguin, θ = incline angle, μs = coeff. static friction, μk = coeff. of kinetic friction, Fmin = minimum force, Fmax=maximum force, Fconst = force needed to have the system move at constant velocity. Believe me, if you do this it will pay off in the end because essentially the same equation in terms of symbols answers all the parts with some minor adjustments. Furthermore, you will be able to see the bigger picture of what's going on.
 
kuruman said:
Your work so far is probably OK but it is hard to follow what you are doing because you are substituting numbers right from the start. It is best to find an expression in terms of symbols giving the minimum force in part (a) in terms of symbols not numbers. Use W = weight of penguin, θ = incline angle, μs = coeff. static friction, μk = coeff. of kinetic friction, Fmin = minimum force, Fmax=maximum force, Fconst = force needed to have the system move at constant velocity. Believe me, if you do this it will pay off in the end because essentially the same equation in terms of symbols answers all the parts with some minor adjustments. Furthermore, you will be able to see the bigger picture of what's going on.
okay thank you for the tip, my professor does this too i should probably adapt that habit.
 
isukatphysics69 said:
okay thank you for the tip, my professor does this too i should probably adapt that habit.
I agree with your professor 200%. It's a good habit because
(a) You can enter the formula and the input variables in something like a spreadsheet and calculate the answer in no time. This eliminates or helps troubleshoot calculation errors because recalculation is easy.
(b) If the answer is incorrect you can troubleshoot it by performing dimensional analysis and, if that fails, check your algebra easily lest you forgot a given quantity, squaring what needs to be squared, starting with an incorrect equation, etc.
 
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ok for part b i am getting 46.2 Newtons

Answers = a.)8.6N, b.) 46.2N, c.) 38.6N
 
isukatphysics69 said:
ok for part b i am getting 46.2 Newtons

Answers = a.)8.6N, b.) 46.2N, c.) 38.6N
Those all look right.
 
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haruspex said:
Those all look right.
I agree.
 
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YES! Thank you guys
 

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