Percent uncertainty in Volume of a beach ball?

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Homework Help Overview

The discussion revolves around calculating the percent uncertainty in the volume of a spherical beach ball, given a specific radius and its uncertainty. The subject area includes concepts of geometry and uncertainty in measurements.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the correct formula for the volume of a sphere and question the original poster's use of the formula for area. There are discussions about methods to determine percent uncertainty, including comparing volumes with varying radii and using rules of thumb related to multiplication of errors.

Discussion Status

The discussion is ongoing, with participants providing different perspectives on how to approach the problem. Some guidance has been offered regarding the relationship between radius and volume uncertainty, but no consensus has been reached on a specific method or formula.

Contextual Notes

There is mention of confusion regarding the teacher's explanations and the potential miscommunication about the radius of the beach ball.

eddiedowen
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Homework Statement


What, roughly, is the percent uncertainty in the volume of a spherical beach ball whose radius is r=5.60±0.05m?


Homework Equations


∏r^2


The Attempt at a Solution

 
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Are you sure that pi*r^2 is the volume of a sphere?
 
I know that pi*r^2 isn't the volume of the sphere but I couldn't remember the formula for the volume of a sphere and regardless, I'm still not sure how to find the percent uncertainty, because my physics teacher isn't very clear when explaining things and it's really difficult to get the just of what he's saying.
 
As Yogi Berra would say, you could look it up.

Obviously, you could compare the volumes of a ball where the radii are 0.05 m greater or less than a radius of 5.60 m, which is more of a beach balloon. Are you sure the radius of the ball is 5.6 m?

Or, you could take the cool approach using calculus.
 
Since you say "roughly", there is a rule of thumb that when quantities multiply, their percentage errors add. Since this is a volume problem, it must involve a product of three distances (and since the radius, r, is the only distance involved, radius cubed). That is, the percentage error in the volume is three times the percentage error in the radius.
 
Accidental double post.
 

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