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Percentage error in Maxwellian distribution.

  1. Jun 1, 2016 #1
    1. The problem statement, all variables and given/known data
    In computing the average kinetic energy of a molecule obeying Maxwellian distribution one use the formula ½mc2 .Calculate the percentage error incurred in the calculation.
    3. The attempt at a solution
    Here c is the average velocity of a molecule obeying Maxwellian distribution which I can calculate which is √(8KT/πm), but I have no idea how to calculate the percentage error so no attempt has been made.

    Thanks
     
  2. jcsd
  3. Jun 1, 2016 #2

    BvU

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    Hello debjit,

    What equation did you use to calculate the average kinetic energy ?
    Do you know the equation for the standard deviation ?
     
  4. Jun 1, 2016 #3
    Thanks for the reply BvU.
    I used Maxwell's velocity distribution to compute average or mean speed

    Maxwell's velocity distribution
    dNc = 4πN(m/2πkT)3/2e-(mc2/2kT)c2dc

    From this I computed the average or mean speed
    c' = 1/N ( o cdNc)

    c' = √(8kT/πm)

    "Do you know the equation for the standard deviation ?"
    Well I am not very much good at the statistical part ,so if you kindly explain it it will be very helpful.

    Thanks
     
  5. Jun 1, 2016 #4

    BvU

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    Well, you can always look it up ...
    usually you do something like ##<x^2> - <x>^2##, so you're halfway already :smile:
     
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