Percentage error in Maxwellian distribution.

1. Jun 1, 2016

debjit625

1. The problem statement, all variables and given/known data
In computing the average kinetic energy of a molecule obeying Maxwellian distribution one use the formula ½mc2 .Calculate the percentage error incurred in the calculation.
3. The attempt at a solution
Here c is the average velocity of a molecule obeying Maxwellian distribution which I can calculate which is √(8KT/πm), but I have no idea how to calculate the percentage error so no attempt has been made.

Thanks

2. Jun 1, 2016

BvU

Hello debjit,

What equation did you use to calculate the average kinetic energy ?
Do you know the equation for the standard deviation ?

3. Jun 1, 2016

debjit625

I used Maxwell's velocity distribution to compute average or mean speed

Maxwell's velocity distribution
dNc = 4πN(m/2πkT)3/2e-(mc2/2kT)c2dc

From this I computed the average or mean speed
c' = 1/N ( o cdNc)

c' = √(8kT/πm)

"Do you know the equation for the standard deviation ?"
Well I am not very much good at the statistical part ,so if you kindly explain it it will be very helpful.

Thanks

4. Jun 1, 2016

BvU

Well, you can always look it up ...
usually you do something like $<x^2> - <x>^2$, so you're halfway already