Permutations (last question of sheet, yay )

  • Thread starter Thread starter karnten07
  • Start date Start date
  • Tags Tags
    Permutations
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 2K views
karnten07
Messages
206
Reaction score
0
Permutations (last question of sheet, yay!)

1. Homework Statement [/b]

[tex]\eta[/tex]:=
(1 2 ... n-1 n)
(n n-1 ... 2 1)
[tex]\in[/tex]S[tex]_{n}[/tex] for any n[tex]\in[/tex]N
n.b That should be 2 lines all in one large bracket btw
a.) Determine its sign.

b.) Let n [tex]\geq[/tex]1. Let <a1,...,as> [tex]\in[/tex]Sn be a cycle and let [tex]\sigma[/tex][tex]\in[/tex]Sn be arbitrary. Show that

[tex]\sigma\circ[/tex] <a1,...,as> [tex]\circ[/tex][tex]\sigma^{-1}[/tex] = <[tex]\sigma[/tex](a1),...,[tex]\sigma[/tex](as)> in Sn.

Homework Equations





The Attempt at a Solution



I get the sign of the permutation to be (-1)^n/2

I don;t know how to do the second part, any ideas?
 
Last edited:
Physics news on Phys.org
Actually, i thought i had done the first part, but i haven't because I am stuck on how to show that for negative numbers, i want the n/2 to be taken as the rounded down value. For example if n=7 i want n/2 to be taken as 3. Is there is a simple way to do this for odd numbers but also keep the same form for positive values of n.

Also it should be (-1)^(n-2/2)

So it should be (-1)^(n-2/2) for even numbers of n and (-1)^(n-3/2) for odd values of n, is there a neater way to do this?
 
Last edited:
I have just said for even numbers of n, that is, n/2 [tex]\in[/tex]Z and for odd numbers, that is n/2[tex]\notin[/tex]Z to distinguish between the two cases.

Im still thinking through part b.) so any help is welcomed.