Phase difference between points on wall

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The discussion focuses on calculating the phase difference between two points on a wall due to parallel water waves striking it at an angle of 30 degrees. The wavelength of the waves is given as 10 meters, and the distance between the two points on the wall is 5 meters. To find the phase difference, the wave needs to advance 2.5 meters, calculated using the sine of the angle. The correct phase difference is determined to be 90 degrees, with clarification that the calculation involves radians. The final consensus confirms that the phase difference of 90 degrees is accurate.
songoku
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Homework Statement


Parallel water waves of wavelength 10 m strike a straight sea wall. The wavefronts make an angle 30o with the wall. What is the difference in phases between the waves at two points 5 m apart along the wall?
a. 30o
b. 45o
c. 90o
d. 156o
e. 180o

Homework Equations


Δφ = Δx / λ

The Attempt at a Solution


I don't think I can just put Δx = 5 m and calculate using the formula but I have no idea how to start. How can the angle given being used to find the phase difference?

Thanks
 
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songoku said:
How can the angle given being used to find the phase difference?
Draw a diagram of a wavefront striking a point on the wall. Now look at a point 5m further along the wall, which the wavefront hasn't reached yet. How far will the wave need to advance to reach that point?
 
Let me try:
the wave needs to advance for 2.5 m (5 sin 30o) so the phase difference = 2.5 / 10 rad = 90o

Is that correct? Thanks
 
songoku said:
Let me try:
the wave needs to advance for 2.5 m (5 sin 30o) so the phase difference = 2.5 / 10 rad = 90o

Is that correct? Thanks
90° is correct, but you mean 2.5/10 (2π) radians.
 
haruspex said:
90° is correct, but you mean 2.5/10 (2π) radians.
Yes, my bad

Thank you very much haruspex
 
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