# Phasor Leading and Lagging Angles

Consider two voltage phasors:

V1 = 1 volt @ 50°, and
V2 = 1 volt @ 30°.

It follows then that the relative phase shift between these two phasors can be expressed by any of the four following descriptions in terms of leading and lagging angle relationships.

1.) V1 Leads V2 by 20°
2.) V1 Lags V2 by 340°
3.) V2 Leads V1 by 340°
4.) V2 Lags V1 by 20°

My question is: By using the above lead/lag positive angle displacements, does is make any sense or is it possible to instead express these same angles in terms of their corresponding negative angle displacements? If you could express it in terms of negative angles how would it be done? Would it negate a lead or lag?

ie. Modify description 1.) to V1 Leads V2 by 20° OR EQUIVALENTLY -340°

I just want to know if this is legal mathematically/conceptually or even makes sense. Some links or references to conventions or interpretations would be nice. Thanks in advance.

NascentOxygen
Staff Emeritus
V1 lags V2 by 340°
V1 lags V2 by -20°

The sinusiod is cyclic, so the general expression is V1 Leads V2 by (20° + n360°) for any integer n ≥ 0.

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V1 lags V2 by 340°
V1 lags V2 by -20°

The sinusiod is cyclic, so the general expression is V1 Leads V2 by (20° + n360°) for any integer n ≥ 0.

2.) If n≥0 why did you express "V2 leads V1 by -20°"
3.) The terms "Lead" and "Lag" already contain information about which way to traverse the angle from the REFERENCE phasor. What does the negative mean in "V2 leads V1 by -20°"?

Typically V1 lags V2 by 20° means rotate C.W. starting from phasor V2 (REFERENCE) by 20°. So in this case we must traverse the plane in the negative angle (lagging or C.W.) direction, however i don't understand saying both leading or lagging AND -20°. It seems that this would be a double negative. Can you clarify what you mean by this?

NascentOxygen
Staff Emeritus