MHB Phasor to sinusoid conversion help

  • Thread starter Thread starter bryanhpaul
  • Start date Start date
  • Tags Tags
    Phasor
Click For Summary
To convert the phasor V = 169∠-45° at a frequency of 60Hz to a sinusoidal function, the angular frequency is calculated using the formula ω = 2πf, resulting in ω = 2π(60) = 377 rad/s. The sinusoidal representation is then expressed as 169cos(377t - 45°) V. The distinction between frequency in Hz and angular frequency in rad/s is crucial, as they are measured in different units. Understanding this conversion is essential for accurate waveform representation. The discussion emphasizes the importance of recognizing the relationship between frequency and angular frequency in electrical engineering.
bryanhpaul
Messages
1
Reaction score
0
Convert the following phasor to sinusoid:

V = 169\angle-45degrees where f = 60Hz

The answer given is 169cos(377t - 45degrees) V

I am sure I am missing something, but how does the frequency go from 60 to 377?
 
Mathematics news on Phys.org
You just multiply by 2(pi). :)
 
A little bit more detail, to expand on dstorm's post:

$$\omega = 2\pi f,$$
where $\omega$ is the angular frequency (that shows up multiplying $t$ in the waveform), and $f$ is just the frequency. Typically, the units will be a tip-off: $f$ is usually measured in Hz, whereas $\omega$ is usually measured in rad/s.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 26 ·
Replies
26
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 20 ·
Replies
20
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K