Photoelectric effect and maximum kinetic energy

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doc.madani
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Hey guys, assume that i performed and experiment to measure the maximum kinetic energy of electrons released due to the photoelectric effect due to light falling on a metal target (i.e. Sodium).

KE = hf - W (where W = work function, f = frequency and h = Planck constant)

since KE = 1/2 mv^2

i need to find the work function of this metal due to the photoelectric effect, do i assume the the velocity of the electron (or photon confused :S) is traveling at 3x10^8 (c) ??

p.s. i have all other known variables excluding W

thanks.
 
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Oh very sorry i was not given the kinetic energy, however i knew the mass of the particle.
can't remember whether it was a photon or electron. In terms of calculating the work function for this particular experiment, is it the absorbed photons we need to consider in determining the work function?

very sorry for this silly question
 
So what exactly is this "experiment"?

You said that the experiment is to measure the max. KE. In most experiment, this is measured "directly", i.e. independent of the values of the work function, etc. In a standard photoelectric effect experiment, the max. KE is related to the stopping potential. So you get the value of the max. KE directly. This gives you ALL you need to find the work function of the metal.

Zz.
 
ZapperZ said:
So what exactly is this "experiment"?

You said that the experiment is to measure the max. KE. In most experiment, this is measured "directly", i.e. independent of the values of the work function, etc. In a standard photoelectric effect experiment, the max. KE is related to the stopping potential. So you get the value of the max. KE directly. This gives you ALL you need to find the work function of the metal.

Zz.

so then just say the stopping potential was 1.6 volts, how would you go on calculating W.
 
thank you very much for that link explained a lot, and no its not school-type work, its simply personal leisure.