Physics 12: Acceleration of Proton in B-Field

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SUMMARY

The discussion focuses on calculating the acceleration of a proton accelerated through a potential difference of 2000 V and entering a magnetic field of 0.50 T. The key equations utilized include \( a = \frac{v^2}{2d} \) for linear acceleration and \( F = qvB \) for centripetal acceleration in the magnetic field. To determine the final velocity of the proton, energy conservation principles are applied. The problem highlights the necessity of calculating both linear and centripetal accelerations to fully understand the proton's motion.

PREREQUISITES
  • Understanding of electric potential difference and its effect on charged particles
  • Familiarity with Newton's second law of motion (F=ma)
  • Knowledge of magnetic force on charged particles (F=qvB)
  • Basic principles of energy conservation in physics
NEXT STEPS
  • Learn how to calculate the final velocity of a charged particle using energy conservation principles
  • Study the effects of magnetic fields on charged particles, focusing on circular motion
  • Explore the relationship between electric fields and potential difference in particle acceleration
  • Investigate the concept of centripetal acceleration in the context of charged particles in magnetic fields
USEFUL FOR

Students studying physics, particularly those focusing on electromagnetism and particle dynamics, as well as educators seeking to explain the motion of charged particles in electric and magnetic fields.

marysaf
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Homework Statement


[/B]
A proton is accelerated from rest at the positive plate of two charged parallel plates with a potential difference of 2000 v. After leaving the plates through a small hole in the negative plate, it enters a uniform magnetic field of 0.50 T in a direction perpendicular to the magnetic field directed out the page as shown in the diagram. Find the acceleration of the proton.
upload_2017-6-4_14-1-59.png

https://drive.google.com/file/d/0B_FmHNxGrZAcN21ic0kwQ191alpram5qc0loclFhRFZTN3Yw/view?usp=sharing

Homework Equations



a=v^2/2d

The Attempt at a Solution



I tried to use the equation above but I don't have d and don't know how to find it. should I use f=ma?
 
Last edited by a moderator:
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marysaf said:
should I use f=ma?
Yes.
 
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marysaf said:

Homework Statement


[/B]
A proton is accelerated from rest at the positive plate of two charged parallel plates with a potential difference of 2000 v. After leaving the plates through a small hole in the negative plate, it enters a uniform magnetic field of 0.50 T in a direction perpendicular to the magnetic field directed out the page as shown in the diagram. Find the acceleration of the proton.

https://drive.google.com/file/d/0B_FmHNxGrZAcN21ic0kwQ191alpram5qc0loclFhRFZTN3Yw/view?usp=sharing

https://lh6.googleusercontent.com/SWII9lhrczWbmznSniycfEcDFtVfg1orKhlr4ua9AmkZbKIVm5eUmqZWPcBqWt-2xArx66svycn4BCHaQm8nXaSDU10Jd3dVW85c=w878-h1043-rw

Homework Equations



a=v^2/2d

The Attempt at a Solution



I tried to use the equation above but I don't have d and don't know how to find it. should I use f=ma?
F = qvB also helps.
 
There are two accelerations in this problem.
The linear one, between the plates.
To find this one you must find first the final velocity. Use energy to do that.

The centripetal one. In the magnetic field. Do find this use F=qvB sin(theta).
 

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