# Homework Help: Physics/ Calc 3 Spaceship Question

1. Sep 17, 2014

### frank1234

1. The problem statement, all variables and given/known data

Imagine a 50kg vehicle located at the origin. We wish to navigate this vehicle by means of applying directed force.

From the point (-2000,16000,0)m, you set a course directly back to the origin. A force of 10N is applied in the appropriate direction for 5 seconds. 5 seconds after you discover that another force of 1N was applied directly up during the 5 second push back to the origin

a)What is the vehicle's position when you discover the upward push?

b)To counteract this course deviation, a force of 1N is applied directly down for 5 seconds. At the end of the course correction where is the vehicle?

c)If we are to bring the vehicle to a stop, directly over the origin, by applying a force of 10N for the last 5 seconds, how long will the return trip take?

d)What is the total distance traveled on this trip?

2. Relevant equations

F=ma

3. The attempt at a solution

I solved for part a and got the answer <1999.84,15998.76,0>

I am a little confused on how to go about solving for parts b and c.

Any tips would be greatly appreciated. Thanks

2. Sep 18, 2014

### Simon Bridge

Notes:
It is not clear which direction is "up" - I take it you are assuming that the +y direction is "up", but the problem statement does not say ... another common choice for "up" is the +z direction with the x-y plane representing "ground level", and it seems odd to specify 3D coordinates and then not use one of them.
Vehicles do not normally go "up" at all unless they are some form of aircraft or on a ramp.

The method for doing (b) and (c) is the same as that for doing (a) ... so how did you do (a)?