Physics Concepts in the Pendulum Practical

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The discussion highlights the impact of a flimsy retort stand on the pendulum's motion, causing it to sway during operation. Key physics concepts such as momentum (p=mv) and torque (torque=rmg) are referenced to explain the dynamics involved. The torque generated by the pendulum results from gravitational force acting on its mass, leading to rotation around its pivot. This rotation increases friction at the connection point with the retort stand, contributing to the observed swaying. Understanding these interactions is crucial for analyzing the pendulum's behavior in practical experiments.
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1. The use of a flimsy retort stand meant that when the pendulum was in the motion the retort stand was also swaying slightly. Explain this.



2. p=mv, torque=rmg



3. I am a bit stumped on this one. My teacher suggested I look into the torque of the pendulum - the friction at the point where the pendulum joined the retort stand and the distance that the pendulum was held from the stand. I originally thought that conservation of momentum was the way to go. I know that the initial momentum of the object was zero but I don't really know where to go next with that.
 
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Any help would be greatly appreciated. The torque of the pendulum is caused by the force of gravity acting on the mass of the pendulum, which causes it to rotate about its pivot point. This rotation causes the friction between the pendulum and the retort stand to increase, resulting in a small amount of swaying. As the pendulum swings, the torque increases and decreases, causing the retort stand to sway as well.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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