Physics Homework - Coefficent of friction.

  • Thread starter Huskies101
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  • #1
I understand what to do for single step problems, but I get lost when it comes to multi-stepped. Help, please!

1. A 2000 kg car traveling at 20 m/s slides to a stop over a distance of 200 m on a snowy level road. What is this coefficient of friction between car's tires and the road?

2. A 3000 kg car accelerates along a level road at a rate of 1.5 m/s when 5500 N of force is applied. What is its coefficient of friction?

Honestly, I am completely lost, and I do need help. So please, can you help me?
 

Answers and Replies

  • #2
rl.bhat
Homework Helper
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Kinetic energy lost by the car is equal to the work done by the frictional force.
Coefficient of friction = ...?
 
  • #3
Kinetic energy lost by the car is equal to the work done by the frictional force.
Coefficient of friction = ...?

I know coefficient of friction = us= FnFf. But how do I find Ff? (Frictional force.) Is it the same as the force applied?
 
  • #4
rl.bhat
Homework Helper
4,433
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Frictional force X displacement = Loss of KE
And us = Ff/Fn
 
  • #5
Kinetic Friction Force=the product of the coefficient of the kinetic friction AND the normal force
"Ffk=μkFn"
 

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