A bullet of mass 0.0019 kg moving at 487 m/s embeds itself in a large fixed piece of wood and travels 0.55 m before coming to rest. Assume that the deceleration of the bullet is constant.
What force is exerted by the wood on the bullet?
I think...Vf^2=Vo^2 + 2a(delta X)
The Attempt at a Solution
I don't even know how to set this problem up. I am guessing I am looking for the acceleration?
Much help appreciated.