(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A stone is launched straight up by a slingshot. Its initial speed is 19.8 m/s and the stone is 1.40 m above the ground when launched. Assume g = 9.80 m/s2.

(a) How high above the ground does the stone rise?

wrong check mark m

(b) How much time elapses before the stone hits the ground?

2. Relevant equations

D= Vot + (1/2)at^2

V=at+Vo

3. The attempt at a solution

Vi=19.8m/s

d=1.4m

a=-9.8m/s

I actually solved another question I had while typing it up on here.. maybe this one will be the same.

Ok, I've attacked this thing every way I can think of, and my problem is the integration of it being launched from 1.4m above the ground. I tried 1.4=19.8t+ (1/2)(-9.8)t^2, solving quadratically for t=3.9688 and t=.071987, neither of which are correct. I know finding the time is the key to the solution, but im not sure how to integrate the 1.4m into the formula.

Can someone point me in the right direction?

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# Homework Help: [111] Throw-up problem - Launch/freefall

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