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WPCareyDevil
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Homework Statement
A stone is launched straight up by a slingshot. Its initial speed is 19.8 m/s and the stone is 1.40 m above the ground when launched. Assume g = 9.80 m/s2.
(a) How high above the ground does the stone rise?
wrong check mark m
(b) How much time elapses before the stone hits the ground?
Homework Equations
D= Vot + (1/2)at^2
V=at+Vo
The Attempt at a Solution
Vi=19.8m/s
d=1.4m
a=-9.8m/s
I actually solved another question I had while typing it up on here.. maybe this one will be the same.
Ok, I've attacked this thing every way I can think of, and my problem is the integration of it being launched from 1.4m above the ground. I tried 1.4=19.8t+ (1/2)(-9.8)t^2, solving quadratically for t=3.9688 and t=.071987, neither of which are correct. I know finding the time is the key to the solution, but I am not sure how to integrate the 1.4m into the formula.
Can someone point me in the right direction?