1. The problem statement, all variables and given/known data A stone is launched straight up by a slingshot. Its initial speed is 19.8 m/s and the stone is 1.40 m above the ground when launched. Assume g = 9.80 m/s2. (a) How high above the ground does the stone rise? wrong check mark m (b) How much time elapses before the stone hits the ground? 2. Relevant equations D= Vot + (1/2)at^2 V=at+Vo 3. The attempt at a solution Vi=19.8m/s d=1.4m a=-9.8m/s I actually solved another question I had while typing it up on here.. maybe this one will be the same. Ok, I've attacked this thing every way I can think of, and my problem is the integration of it being launched from 1.4m above the ground. I tried 1.4=19.8t+ (1/2)(-9.8)t^2, solving quadratically for t=3.9688 and t=.071987, neither of which are correct. I know finding the time is the key to the solution, but im not sure how to integrate the 1.4m into the formula. Can someone point me in the right direction?