1. The problem statement, all variables and given/known data The moon is smaller than the earth and has a weaker gravity. On the moon's surface, the acceleration due to gravity is 1.6 m/s^2. You are on the moon and you throw a moon rock straight up. It reaches a height of 44 m. a) Find the moon rock's initial velocity. b)Find the total time of the moon rock's flight. 2. Relevant equations v0^2=v^2-2αΔy t^2 =2y/a 3. The attempt at a solution a) v0^2 =0-2(1.6 m/s^2)(44 m) √v0^2=√140.8 v0=11.9 m/s b) t^2 =2y/a t^2= 88 m/1.6 m/s^2 Taking the square roots of both sides: t=55 s. Are these answers correct? This is a newer concept to me, so input would be greatly appreciated!