Physics: Images through Thin Lenses

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SUMMARY

The discussion centers on the analysis of a thin lens with parameters p = 75 cm, n = 1.55, r1 = 30 cm, and r2 = -42 cm. The calculations yield an image distance (i) of 55.26 cm and a magnification (m) of -0.74. The confusion arises regarding the nature of the image; while the calculations indicate an inverted image due to the negative magnification, the drawing suggests a non-inverted, virtual image. The correct interpretation is that the image is indeed virtual and non-inverted, as the drawing reflects the behavior of light rays through the lens.

PREREQUISITES
  • Understanding of thin lens formula: 1/p + 1/i = 1/f
  • Familiarity with magnification calculations: m = -i/p
  • Knowledge of lens parameters: object distance (p), image distance (i), focal length (f)
  • Basic principles of ray diagrams for lenses
NEXT STEPS
  • Study the derivation and application of the thin lens formula in various scenarios
  • Explore the concept of virtual vs. real images in optics
  • Learn how to construct accurate ray diagrams for different types of lenses
  • Investigate the effects of lens curvature on image formation
USEFUL FOR

Students of physics, optical engineers, and educators seeking to deepen their understanding of lens behavior and image formation principles.

JCUghetta
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A thin lenses with given p = 75cm, n = 1.55, r1 = 30cm, and r2 = -42cm.
Find the a.) i b.) m c.) Is the image real or virtual d.) Is the image inverted or noninverted e.) Is the image on the same or opposite side as the object

Using 1/p + 1/i = 1/f and also 1/f = (n-1)*(1/r1 - 1/r2) I solved for a.) i = 55.26 cm
For b.) m = -i/p; so m = -0.74

From drawing out this picture of the thin lenses and drawing the inward and outward light rays, I got a c.) that the image is virtual, and d.) that the image is non-inverted. But based on the math, because m is equal to a negative value, it should be an inverted image.

Why does my drawing show a non-inverted image but using the math I solved to get m show an inverted image? Which one of these is right? Thanks in advance.
 
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JCUghetta said:
A thin lenses with given p = 75cm, n = 1.55, r1 = 30cm, and r2 = -42cm.
Find the a.) i b.) m c.) Is the image real or virtual d.) Is the image inverted or noninverted e.) Is the image on the same or opposite side as the object

Using 1/p + 1/i = 1/f and also 1/f = (n-1)*(1/r1 - 1/r2) I solved for a.) i = 55.26 cm
For b.) m = -i/p; so m = -0.74

From drawing out this picture of the thin lenses and drawing the inward and outward light rays, I got a c.) that the image is virtual, and d.) that the image is non-inverted. But based on the math, because m is equal to a negative value, it should be an inverted image.

Why does my drawing show a non-inverted image (without knowing your drawing this question is really hard to answer) but using the math I solved to get m show an inverted image? Which one of these is right? Thanks in advance.

Good evening,

with p = 75 cm (I assume that this is the distance of the object from the lens?) and
i = 55,26 cm (I assume that this is the distance of the image from the lens?)
and $$f = \tfrac{350}{11} \ cm$$

you should get a real image which is inverted (if you mean by inverted that the image is upside down in comparison to the object).

If it is possible for you please post your drawing including some additional remarks of how you have made this drawing.
 

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