- 367
- 0
V_2-V-1 is determined by the charge q_1,
V_3-V_2 is determined by q_1+q_2
V_3-V_2 is determined by q_1+q_2
Where does q_3 figure then?V_2-V-1 is determined by the charge q_1,
V_3-V_2 is determined by q_1+q_2
Yes! Now set V_3-V_1 equal to zero...[itex]V_2-V_1=\frac{q_1}{4\pi\epsilon}(1/r-1/2r) [/itex]
[itex]V_3-V_2=\frac{q_1+q_2}{4\pi\epsilon}(1/2r-1/3r) [/itex]
Sorry, yes! You need V_3-V_1, and then set the result equal to zero.[itex]V_2-V_1=\frac{q_1}{4\pi\epsilon}(1/r-1/2r)[/itex]
[itex]V_3-V_2=\frac{q_1+q_2}{4\pi\epsilon}(1/2r-1/3r)[/itex]
So I add these equations?
Not quite....you made a small mistake in the addition[itex]V_3-V_1=\frac{q_1}{4\pi\epsilon r}+\frac{q_2}{4\pi\epsilon 6r}=0?[/itex]