Physics Question Regarding Impluse, Momentum, and Velocity.

[Jim4592]

I'm not sure exactly sure how to set up this problem...

Homework Statement

A hockey puck with a mass of 0.160 kg is at rest at the origin (x=0) on a horizontal, frictionless surface at time t=0, a force of 0.250 N is applied to the puck parallel to the X axis, the force is applied until time = 2.00s.

Homework Equations

What is the acceleration, position, and speed of the puck at t=2.00 s

The Attempt at a Solution

Impulse (J) = (F) * (∆T)
J = (0.250N)*(2.00s)
J = .5 NS

I know J = ∆ Momentum (P) ; and P = Mass * Velocity, but I'm not exactly sure how to calculate what it wants me to find.

Any help will be appreciated.

Thanks,

Jim

 

[Doc Al]

You have the force. What does that tell you about the acceleration?
You found the impulse. What does that tell you about the speed at t=2.00s?
Use a little kinematics to find the distance traveled.

 

[Jim4592]

I think i get it but aren't completely sure

so using P=mv
.5 NS = 0.160 kg * v

v= 3.125 m/s ?

A = (3.125 m/s) / 2.00s
A = 1.563 m/s^2

and position:
X(final) = X(initial) + V(i)t + 1/2 at^2
X = 1/2 * (1.563 m/s) * (2.00s)^2
X = 3.125m

Could someone confirm that is correct please?

 

[Doc Al]

All good!

 

[Jim4592]

wow that was a lot easier than i thought. Thanks for your help.