Piece-Wise Function Continuity

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SUMMARY

The discussion focuses on determining the continuity of the piece-wise function defined as f(x) = {x^3 if x ≤ -2, 2 if x > -2}. The function is continuous at x = -2 if the three conditions for continuity are satisfied: f(c) exists, the limit as x approaches c exists, and the limit equals f(c). The left-hand limit as x approaches -2 is -8, while the right-hand limit is 2, indicating that the function is discontinuous at x = -2 due to the failure of the limit condition.

PREREQUISITES
  • Understanding of piece-wise functions
  • Knowledge of limits in calculus
  • Familiarity with continuity conditions in mathematics
  • Basic algebra skills for evaluating functions
NEXT STEPS
  • Study the concept of limits and how to calculate them for piece-wise functions
  • Learn about the formal definition of continuity in calculus
  • Explore examples of discontinuous functions and their classifications
  • Practice evaluating limits from both sides for various functions
USEFUL FOR

Students studying calculus, particularly those learning about continuity and limits, as well as educators looking for examples of piece-wise function analysis.

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Homework Statement


Determine whether the given function is continuous. If it is not, identify where it is discontinuous and which condition fails to hold.

f(x)= {x^3 if x < or = -2
{2 if x > -2


Homework Equations


The conditions are that a function is said to be continuous at x=c if the following conditions hold:
1 f(c) exists
2 lim as x approaches c f(x) exists
3 lim as x approaches c f(x) = f(c)



The Attempt at a Solution


My professor has not explained this and has assigned it...no clue what to do!
 
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You will have to calculate the limit in each point and see whether the left and right sided limits are equal.
 

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