Pin Connection with one support reaction?

[RadiationX]

Please click on the image to make it bigger.

http://img105.imageshack.us/img105/5413/pinconnectiontw4.th.jpg

At pin connnection G shouldn't there be two support reactions just like the pin connection at A?


If the solution in the diagram is correct why is it correct?

 

[Mentz114]

The link is not working. I can't access your diagram.

 

[RadiationX]

It is working for me. Do you have a pop-up blocker on? The link pops up in a new tab for me( runnning Firefox).

If that won't work, right click on the image and select copy image location and paste that into your browser.

 

[Mentz114]

Sorry, there's no response from the site whatever method I use.

I'm outside the USA, maybe that's it.

 

[RadiationX]

um, I posted the same question to another board. You can check it out athttp://www.sosmath.com/CBB/viewtopic.php?p=135924#135924"

I'd like to know if you have the same problem there as well.

 

[Mentz114]

OK, I got the pic. There's only one member connected to G, so only one reaction, but two on A. Is that what's troubling you ?

 

[RadiationX]

Yes, so if there is only one member connectecd then only one reaction is needed? I thought that pin connection always had two reactions regardless of the members.BTW thank you.

 

[Mentz114]

In a statics problem, one resolves the forces at each node with the constraint that the total is zero because nothing is moving.

At A there are two forces to be resolved into the horizontal reaction, at G there's only one.

I don't see what is causing you a problem. Am I missing something.

 

[RadiationX]

No, I was missing something. You cleared it up for me :O

 

[aajivani75]

No, I was missing something. You cleared it up for me :O

i m not still clear please help me out. Both A and G are pin connected then why there is one support reaction at G and two at A

 

[PhanthomJay]

i m not still clear please help me out. Both A and G are pin connected then why there is one support reaction at G and two at A

Members subject to forces at their hinges only (a force at each end, with no forces in between the ends) are known, appropriately, as "two-force" members, and in order for the member to be in equilibrium, the forces acting on the member at each end must be equal and opposite and co-linear, acting along the longitudinal 'axial' axis of the member. Since the sole member at G is horizontal, the force acting on it at the pin, G, must be horizontal, with no vertical component.

 

[aajivani75]

Members subject to forces at their hinges only (a force at each end, with no forces in between the ends) are known, appropriately, as "two-force" members, and in order for the member to be in equilibrium, the forces acting on the member at each end must be equal and opposite and co-linear, acting along the longitudinal 'axial' axis of the member. Since the sole member at G is horizontal, the force acting on it at the pin, G, must be horizontal, with no vertical component.

Thanks a lot i got it :)