DaTario
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Hi All,
Suppose you have a spring with a given elastic constant k. Its natural width is L = 1 meter and its mass is M = 0.1 kg. Now imagine you put this spring to oscilate, with its ends fixed, forming a pure second harmonic oscilation, plane polarized, with frequency Omega. The amplitude of this oscillation is A = 1 meter also.
How is one to determine the energy E of this system ? (mechanical energy of this system E = Ekin + Epot)
P.S. it seems natural that the frequency Omega is to be determined from the constants I alluded above.
P.S. 2: by second harmonic I mean a sine function between the end points (x = 0 and x = 1) with just one crest and one valley.
Best Regards
DaTario
Suppose you have a spring with a given elastic constant k. Its natural width is L = 1 meter and its mass is M = 0.1 kg. Now imagine you put this spring to oscilate, with its ends fixed, forming a pure second harmonic oscilation, plane polarized, with frequency Omega. The amplitude of this oscillation is A = 1 meter also.
How is one to determine the energy E of this system ? (mechanical energy of this system E = Ekin + Epot)
P.S. it seems natural that the frequency Omega is to be determined from the constants I alluded above.
P.S. 2: by second harmonic I mean a sine function between the end points (x = 0 and x = 1) with just one crest and one valley.
Best Regards
DaTario
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