Please check my solutions -- Mass being pulled with an angled rope

AI Thread Summary
The discussion focuses on calculating the work done by a force F on a block of mass M, considering friction and normal forces. The force F of 100 N is applied at a 60-degree angle, and the friction force is determined using the formula f = μN, not f = μmg. The normal force N must be calculated correctly, as the applied force's angle affects its vertical component. The correct equation for the normal force includes the downward component of the applied force, leading to N - 100sin(60) = 4 * 9.81. Accurate calculations of these forces are essential for determining the work done.
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A block of mass M = 4 kg is pulled by a force F = 100 N forming an angle of 60 degrees with themhorizontal plane with friction coefficient 0.3.

Determine the work of force F, friction force and normal force.

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Welcome to PF. :smile:

On your first solution, what are units of "S" for work? What units should Work be in?
 
I assume S to be the displacement?
 
rsk said:
I assume S to be the displacement?
Oh, thanks. I guess the displacement is indeed a variable -- I missed that.
 
The friction force is $$f=\mu N$$ and NOT $$f=\mu mg$$. So to correctly determine the friction force you need to find the normal force N first.
Your equation for the normal force N doesn't seem correct either (though the final result might be correct), it should be $$N-100\sin60=4\cdot 9.81$$ i.e. the force of 100N is actually forming an angle of -60 degrees with the horizontal, that is it is pointing down not up.
 
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