Please explain my answer in Proof Inequalities

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Homework Help Overview

The discussion revolves around a proof involving inequalities and absolute values. The original poster claims to have solved the problem correctly, matching the answer provided in a textbook, and seeks clarification on the validity of their solution.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the validity of the original poster's approach, questioning the correctness of their simplification involving absolute values. There is an exploration of different cases based on the values of x to properly handle the absolute values.

Discussion Status

The discussion is ongoing, with some participants suggesting that the original poster's method may be flawed while others provide insights into how to approach the problem by considering various cases for x. There is no explicit consensus on the correctness of the original poster's solution.

Contextual Notes

Participants emphasize the importance of considering different cases when dealing with absolute values and the implications of assumptions made during the problem-solving process. The original poster's assumptions and the conditions under which their solution holds are under scrutiny.

phillyolly
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Homework Statement



I solved the problem and it matches the answer at the end of the book.
Please explain why am I right? Why these two answers are correct?
THank you

Homework Equations





The Attempt at a Solution

 

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You simply got extremely lucky with your first work - it is never correct to simplify

<br /> |x+1| + |x-2| = |x|+1 + |x| -2<br />

as you did.
 
Do you imply that my approach is incorrect and need to be changed? Is it only my first part incorrect? The second one is alright?
 
You need to think of a few cases here.

1) When x+1 AND x-2 > 0, so that leaves x>-1. When you make this assumption you can get rid of the absolute value signs since it is, by your assumption, more than zero anyway so nothing changes.

2) When x+1>0 and x-2<0, so we restrict x to -1<x<2. Since one of the absolute values are less than zero, you need to take the negative of it when removing the absolute value sign.

3) When both are less than zero.

And you can include when x=-1,2 where necessary. Remember that since in each case, you make an assumption on what x is. When you solve the problem for that case, if x turns out to be something outside of the domain of your assumption, then that answer is invalid. For example, in case two if you end up solving the problem and get x=4, then the answer isn't valid since we already assumed for that case, -1<x<2.
 

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