Given the parametric function defined by x = a cos ^3t, y = a sin^3t, plot the curve. So I converted the above to (x/a)^(2/3) + (y/a)^(2/3) = 1, and from that got y +-a(1-(x/a)^(2/3))^(3/2). However, I have no idea of how to actually plot a function of this form. Is my only choice to make a table? I also have to find the area of the region enclosed by this function. To do this, I need to find the integral of y(t)x'(t)dt from alpha to beta. However, y(t)x'(t)dt = sin^4tcos^2tdt and I can't find a proper u-substitution for integration. Thanks for any help!