Plotting Level Set f(x,t)=2: Struggling to Find Equation

[bizzo342]

I'm having a really hard time with this question...

Consider the function g: [0,infinity) --> R shown in figure 7 (Figure 7 is just a graph of a curve defined as z=g(s), where the horizontal axis is the s-axis) Let f be a new function given by: z = f(x,t) = g((x^2)+(t^2)-1). Plot the level set: f(x,t)=2. Classify the surface f.

My problem is that it doesn't give me an equation to stick the input into, just some graph ...help!

 

[HallsofIvy]

And I don't even have the graph!
$$f(x,y)= g(x^2)+ y^2- 1= 2$$
$$g(x^2)+ y^2= 3$$
If g is linear (if the graph is a straight line), with positive slope, then this is an ellipse; with negative slope, a hyperbola. Whatever g is, we can see that the surface will be symmetric in both x and y. Without having some idea of what the graph of g looks like, I don't think we can say more.