Plotting Level Set f(x,t)=2: Struggling to Find Equation

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SUMMARY

The discussion revolves around plotting the level set of the function f(x,t) = g((x^2) + (t^2) - 1) and specifically finding the conditions under which f(x,t) = 2. The transformation leads to the equation g(x^2) + y^2 = 3, indicating that the nature of the surface depends on the characteristics of the function g. If g is linear with a positive slope, the resulting surface is an ellipse; if g has a negative slope, it forms a hyperbola. The symmetry of the surface in both x and y axes is confirmed, but further classification requires knowledge of the graph of g.

PREREQUISITES
  • Understanding of level sets in multivariable calculus
  • Familiarity with the properties of conic sections (ellipses and hyperbolas)
  • Knowledge of function transformations and their implications
  • Basic graphing skills for visualizing functions
NEXT STEPS
  • Study the properties of level sets in multivariable functions
  • Learn about the classification of conic sections, focusing on ellipses and hyperbolas
  • Explore function transformations and their effects on graphs
  • Investigate specific forms of the function g to understand its impact on the surface classification
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Mathematicians, students in multivariable calculus, and anyone interested in understanding the geometric implications of level sets and conic sections.

bizzo342
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I'm having a really hard time with this question...

Consider the function g: [0,infinity) --> R shown in figure 7 (Figure 7 is just a graph of a curve defined as z=g(s), where the horizontal axis is the s-axis) Let f be a new function given by: z = f(x,t) = g((x^2)+(t^2)-1). Plot the level set: f(x,t)=2. Classify the surface f.

My problem is that it doesn't give me an equation to stick the input into, just some graph ...help!
 
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And I don't even have the graph!
f(x,y)= g(x^2)+ y^2- 1= 2
g(x^2)+ y^2= 3
If g is linear (if the graph is a straight line), with positive slope, then this is an ellipse; with negative slope, a hyperbola. Whatever g is, we can see that the surface will be symmetric in both x and y. Without having some idea of what the graph of g looks like, I don't think we can say more.
 

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