Plotting Polar Curves in Mathematica: Troubleshooting Homework Statement

[flyingpig]

Homework Statement

I am trying to plot the two polar curves r = \sqrt{3} cos(\theta) and r = sin(\theta)

Mathematica only gives me one of the curves.

I tried plotting PolarPlot[{sqrt (3) Cos[t]}, {t, 0, 2 Pi}] and it gives me a blank box in the first quadrant.

any ideas?

 

[I like Serena]

Homework Statement

I am trying to plot the two polar curves r = \sqrt{3} cos(\theta) and r = sin(\theta)

Mathematica only gives me one of the curves.

I tried plotting PolarPlot[{sqrt (3) Cos[t]}, {t, 0, 2 Pi}] and it gives me a blank box in the first quadrant.

any ideas?

Try the following?
http://www.wolframalpha.com/input/?i=r+=+\sqrt{3}+cos(\theta)
http://www.wolframalpha.com/input/?i=r+=+sin(\theta)

 

[phyzguy]

That's because it doesn't recognize sqrt(3). Try:

PolarPlot[{Sqrt[3] Cos[t]}, {t, 0, 2 Pi}]

 

[flyingpig]

Neither works

 

[I like Serena]

Neither works

Did you mean the WolframAlpha links?
Those work for me.

And according to WolframAlpha the Mathematica expression for the polar plot is:

PolarPlot[{Sqrt[3] Cos[t]}, {t, -Pi, Pi}]

It seems that it matters what the range of t is, because it does not work from 0 to 2Pi.

 

[flyingpig]

No, I mean your links do work, but they only plot one curve. I am trying to plot both curves together

 

[Mapes]

PolarPlot[{Sqrt[3] Cos[t], Sin[t]}, {t, 0, 2 Pi}] works for me.

 

[flyingpig]

OKay it is working now. thanks