Plotting the Spectrum of a DSB-C Signal

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SUMMARY

The discussion focuses on plotting the magnitude spectrum of a Double Sideband Amplitude Modulated (DSB-C) signal defined by the equation m(t)=0.2sin(w1*t) + 0.5cos(w2*t). The Fourier transform of the signal is given as M(F)=0.25[∂(f-f2)+∂(f+f2)] + 0.1j[∂(f+f1)-∂(f-f1)]. Participants emphasize the importance of using phasor diagrams to represent phase changes for sine and cosine components effectively.

PREREQUISITES
  • Understanding of Fourier Transform principles
  • Familiarity with DSB-C signal modulation techniques
  • Knowledge of phasor diagrams and their applications
  • Basic skills in signal processing
NEXT STEPS
  • Study the properties of Fourier Transforms in signal analysis
  • Learn how to sketch magnitude spectra for various signal types
  • Explore phasor representation for sinusoidal signals
  • Investigate the implications of phase changes in signal processing
USEFUL FOR

Electrical engineers, signal processing students, and professionals involved in communication systems who are interested in understanding and visualizing DSB-C signals.

Natalie89
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I have m(t)=0.2sin(w1*t) + 0.5cos(w2*t) ---> Note: the 1 and 2 besides "w" (omega) is not a coefficient, its a subscript to show that they are different.

I found the Fourier transform to be M(F)=0.25[∂(f-f2)+∂(f+f2)] + 0.1j[∂(f+f1)-∂(f-f1)].

My question is, how do I sketch the magnitude spectra of this?
 
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| M(F) |=0.25[∂(f-f2)+∂(f+f2)] + 0.1[∂(f+f1)-∂(f-f1)].

Phase changes for sin and cos.

These can be better represented by phasor diagrams that you might have or will see soon.
 
Thanks!
 

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