Fatima Hasan
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Fatima Hasan said:Could someone please confirm my answer?
Fatima Hasan said:
Can't read your notes but it looks like your S(f) is the carrier in the frequency spectrum.Fatima Hasan said:Homework Statement:: Attached below.
Relevant Equations:: cos(t) <--> 1/2 [δ (f-fc) + δ(f+fc) ]
Here's my work:
View attachment 279784
View attachment 279782
Could someone please confirm my answer?
Sorry, I don't quite understand. From the image in the picture, it looks as if there are only the two side bands present (and the -ve frequency versions as well)...rude man said:Can't read your notes but it looks like your S(f) is the carrier in the frequency spectrum.
"DSB-SC" has no carrier power in the spectrum.
The sidebands are above and below the carrier frequency.
If you multiply a signal ## sin(\omega_st ## by the carrier ## sin(\omega_ct ## you get DSB-SC spectrum as high school trig will reveal. Sidebands at ## (\omega_c + \omega_s) ## and ##\omega_c - \omega_s ##.