Point of Inflection: Analyze x^2/x-1

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Homework Help Overview

The discussion revolves around analyzing the function f(x) = x^2 / (x - 1), focusing on identifying asymptotes, extrema, and points of inflection.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss deriving the first derivative and the challenges faced in applying the quotient rule and chain rule. There are attempts to reformulate the problem using different mathematical techniques. Questions arise regarding the existence of points of inflection and the implications of the second derivative's sign changes.

Discussion Status

Some participants have provided suggestions for alternative approaches to deriving the first derivative. There is ongoing exploration of the conditions for points of inflection, with differing interpretations of the implications of the second derivative's behavior at specific points.

Contextual Notes

Participants are navigating the complexities of derivative calculations and the definitions of points of inflection, with some uncertainty about the implications of their findings.

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Homework Statement



x^2 / x-1. Identify any asymptotes, extrema and points of inflection.

Homework Equations





The Attempt at a Solution



I am stuck trying to derive my first derivative. My first derivative equals x(x-2)/(x-1)^2. I tried to use the quotient rule again using while incorporating the chain rule and after multiple attempts I kept resulting with 2 / (x-1)^3.

Any suggestions?
 
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This should help in general, switch your quotient rule into a product & chain rule :

##\frac{x^2}{x-1} = x^2 (x-1)^{-1}##
 
mathpat said:

Homework Statement



x^2 / x-1. Identify any asymptotes, extrema and points of inflection.
Write this as an equation, and use parentheses.

f(x) = x2/(x - 1)
mathpat said:

Homework Equations





The Attempt at a Solution



I am stuck trying to derive my first derivative. My first derivative equals x(x-2)/(x-1)^2.
As an equation, this is f'(x) = x(x-2)/(x-1)2.
mathpat said:
I tried to use the quotient rule again using while incorporating the chain rule and after multiple attempts I kept resulting with 2 / (x-1)^3.

Any suggestions?
Your answer is correct, and this can be verified by calculating the derivative using the technique that Zondrina suggested.
 
I see... so basically that means there is no point of inflection since I can not set that equation equal to zero and solve?


By the way, I appreciate both of your help.
 
mathpat said:
I see... so basically that means there is no point of inflection since I can not set that equation equal to zero and solve?
The sign of f'' changes at x = 1. If x < 1, f''(x) < 0, and if x > 1, f''(x) > 0. Does this mean that there is an inflection point at x = 1? Why or why not?
mathpat said:
By the way, I appreciate both of your help.
 

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