Points that are symmetric with respect to a circle C

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SUMMARY

The discussion centers on proving the symmetry of two points, P and P prime, with respect to a circle C defined by its center (x nought, y nought) and radius R. The condition for symmetry is established as y nought tilde being equal to the square root of (y nought squared minus radius squared). Participants emphasize the geometric relationships and suggest simplifying the approach by focusing on the lengths of lines rather than vector notation.

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brcole
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Homework Statement



Lemma 1: Fix the circle C with center (x nought, y nought); y nought is greater than 0 and
radius R is less than y nought. Consider two points P (x nought, y noight tilde) and P prime (x nought, -y nought tilde) which are symmetric with respect to x-axis by construcion.

Prove that P and P prime are also symmetric with respect to Circle C if and only if y nought tilde is equal to the sqrt (y nought squared - radius squared).

Homework Equations


on the attachment



The Attempt at a Solution


I believe that these two points are orthogonal with respect to the x-axis. and they are symmetric because they fall on the same ray.
 

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brcole said:

Homework Statement



Lemma 1: Fix the circle C with center (x nought, y nought); y nought is greater than 0 and
radius R is less than y nought. Consider two points P (x nought, y noight tilde) and P prime (x nought, -y nought tilde) which are symmetric with respect to x-axis by construcion.

Prove that P and P prime are also symmetric with respect to Circle C if and only if y nought tilde is equal to the sqrt (y nought squared - radius squared).

Homework Equations


on the attachment

Hi brcole! Welcome to PF! :smile:

You're making this too complicated …

all the points are on the same "vertical" line …

so just give every point a name, don't use || of vectors, just talk about the length of lines …

Call (x0,0) Q.

Then you have to prove that CP.CP´ = r2,

and you know what CQ and QP and QP´are … :smile:
 

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