B Poisson distribution having variation coefficient = .5?

AI Thread Summary
The discussion centers on the properties of the Poisson distribution, specifically the relationship between the mean (μ) and variance (σ²). It is clarified that for a Poisson distribution, the mean is equal to the variance, which means μ = σ² is incorrect. The confusion arose from mixing up variance and standard deviation. The correct understanding is that in a Poisson distribution, the variation coefficient cannot be 0.5, as it contradicts the fundamental definition. The thread emphasizes the importance of accurately interpreting these statistical concepts.
Addez123
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How is it possible for a variation coefficient of poisson distribution to be anything other than 1?
Variation coefficient is calculated by
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And the very definition of poisson distribution is that
$$\mu = \sigma $$

So how would any other value but 1 be a possible?
 
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μ = σ2
 
gleem said:
μ = σ2
Then its no longer a poisson distribution because the very definition of a poisson distribution is that
μ = σ, not μ = σ2
 
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For a Poisson distribution, the mean is equal to the variance. Check your source.
 
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I see what I did wrong. I mixed up variance and standard deviation.
 
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