Polar Kinematics - omega vs. theta_dot?

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SUMMARY

In polar kinematics, ω (angular speed) and \dot{θ} (the time derivative of the angle θ) are not equivalent despite both being expressed in radians per second. The discussion clarifies that while ω represents the rate of rotation, \dot{θ} specifically describes the angular position's rate of change in polar coordinates. The velocity vector v in polar coordinates is defined as v = \dot{r}\widehat{r} + r\dot{θ}\widehat{θ}, indicating that the components of motion along the radius and around the axis are distinct. Thus, while ω and \dot{θ} can be numerically equal under certain conditions, they represent different physical concepts.

PREREQUISITES
  • Understanding of polar coordinates and their representation.
  • Familiarity with angular speed and its units (rad/s).
  • Knowledge of vector components in polar kinematics.
  • Basic calculus, specifically differentiation with respect to time.
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  • Study the derivation of the velocity vector in polar coordinates.
  • Learn about the relationship between linear and angular velocity.
  • Explore the implications of angular acceleration in polar systems.
  • Investigate the differences between scalar and vector quantities in rotational motion.
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Students and professionals in physics, particularly those focusing on mechanics and kinematics, as well as engineers working with rotational systems and polar coordinate analysis.

mechEstudent
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Are ω and \dot{θ} the same in a polar kinematics?

I know ω is angular speed (rad/s) and it seems to me that \dot{θ} would be the same, but in the context of rotation in polar coordinates where v = \dot{r}\widehat{r}+ r\dot{θ}\widehat{θ}, v = rω, and vθ = r\dot{θ}, that doesn't seem to be true.

If they are not the same, what is the physical meaning of \dot{θ}?
 
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mechEstudent said:
Are ω and \dot{θ} the same in a polar kinematics?

I know ω is angular speed (rad/s) and it seems to me that \dot{θ} would be the same, but in the context of rotation in polar coordinates where v = \dot{r}\widehat{r}+ r\dot{θ}\widehat{θ}, v = rω, and vθ = r\dot{θ}, that doesn't seem to be true.
What you have called v and vθ seem to be the same thing.
 
I could be wrong...

It seems your v is the instanteous velocity vector of a point in space in polar coordinates. The r components describe the motion of a point along the axis of the radius r. The θ components describe the motion of the point about the axis of rotation of θ.

Therefore ω = \dot{θ} = dθ/dt (a scalar speed value).

Symbolic terminology is confusing. Drinking more beer usually corrects this.
 

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