Polar / Rectangular Coordinates

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SUMMARY

The discussion focuses on converting the polar equation r = tan(theta) into rectangular coordinates. The user, Sparky, attempts to derive the relationship using the equations r = √(x² + y²) and cos(theta) = x/r, leading to the equation x√(x² + y²) - y = 0. The expected result from the textbook is x⁴ + (x²)(y²) - y². The solution involves rearranging and simplifying the equation by moving y to the other side, squaring both sides, and expanding the brackets.

PREREQUISITES
  • Understanding of polar coordinates and their conversion to rectangular coordinates
  • Familiarity with trigonometric functions, specifically sine and cosine
  • Knowledge of algebraic manipulation and simplification techniques
  • Basic comprehension of Cartesian coordinate systems
NEXT STEPS
  • Study the conversion formulas between polar and rectangular coordinates
  • Practice solving trigonometric equations involving sine and cosine
  • Explore algebraic techniques for simplifying complex equations
  • Learn about the geometric interpretations of polar and rectangular coordinates
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Students studying mathematics, particularly those focusing on calculus and coordinate geometry, as well as educators looking for examples of polar to rectangular coordinate conversions.

Sparky_
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Homework Statement



Convert into rectangular coordinates:

[tex] r = tan(theta)[/tex]



Homework Equations





The Attempt at a Solution



[tex] r = \frac {sin}{cos}[/tex]


I used
[tex] r = \sqrt{x^2+y^2}[/tex]
and

[tex] cos = \frac {x}{r}<br /> <br /> x = (r)(cos)<br /> sin = \frac {y}{r}<br /> <br /> y = (r)(sin)[/tex]

[tex] \sqrt {x^2+y^2} = \frac{\frac{y}{\sqrt {x^2+y^2}}}{\frac{x}{\sqrt {x^2+y^2}}}[/tex]

Then -

[tex] x\sqrt {x^2+y^2} -y =0[/tex]

The book gets
[tex] x^4 + (x^2)(y^2) - y^2 <br /> [/tex]


Can you help with the simplification to get to the book’s answer?

Thanks
-Sparky
 
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Take y to the other side, square and open brackets.
 
Thanks so much!
 

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