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Polylogarithm identity question

  1. Jul 4, 2009 #1
    I found this equation last night on Wolfram:


    How is it possible this equation has no restrictions given that the gamma function has poles at the negative integers?

    Also, won't the zeta function portion run into problems at those integers as well when k passes v in the summation?
  2. jcsd
  3. Jul 4, 2009 #2


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    Science Advisor

    There are no restrictions because one side is not defined at exactly the points the other is not defined.
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