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Nerd-ho
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Hi, I'm a high school graduate who's been going through some UNISA (University of South Africa) mathematical modelling material and I've come across the following difference equation -
a(n+1) = 1 - a(n).
The answer given in the material was that the solution alternates between a(0) for n even and 1 - a(0) for n odd.
I think I've come up with a solution that holds true for all n, namely:
a(n) = a(0)*-1^n + (-1^n - 1)*(-1/2)
Am I correct?
Regards, Travis
a(n+1) = 1 - a(n).
The answer given in the material was that the solution alternates between a(0) for n even and 1 - a(0) for n odd.
I think I've come up with a solution that holds true for all n, namely:
a(n) = a(0)*-1^n + (-1^n - 1)*(-1/2)
Am I correct?
Regards, Travis
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