Possible Quantum Number Combinations for 2p State

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For the 2p state, the quantum numbers are defined as n=2, l=1, m_l can be -1, 0, or 1, and m_s can be -1/2 or 1/2. When considering two electrons in the 2p state, various combinations of these quantum numbers can occur, ensuring that no two electrons share the same set of quantum numbers. The requirement is that if three quantum numbers are identical, the fourth must differ. This leads to multiple valid configurations for the two electrons. Understanding these combinations is essential for grasping the principles of quantum mechanics in atomic structure.
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Homework Statement


List all possible values for the quantum numbers n, l, m_l and m_s for a state 2p. If an atom has 2 electrons 2p, how many states are there?

Homework Equations


Simple ones.

The Attempt at a Solution


n=2.
l=1.
m_l=-1, 0, 1.
m_s=-1/2, 1/2.
Now I'm confused on how to answer the question.
2 electrons in 2p means 2 electrons with quantum numbers:
(n,l,m_l,m_s)=
(2,1,-1,1/2) and (2,1,-1,-1/2)
or (2,1,-1,-1/2) and (2,1,-1,-1/2)
or (2,1,-1,1/2) and (2,1,0,1/2)
or (2,1,-1,1/2) and (2,1,0,-1/2)
or (2,1,0,1/2) and (2,1,-1,1/2)
or etc.
I mean an electron can have a certain m_l while the other can have any other m_l incuding the same m_l as the first electron. When they have the same m_l, they must have opposite spin. Is this ok?
 
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Yes, the only requirement is that the electrons must not have the same quantum numbers. If 3 of them are identical, the 4th is forced to have different values among them.
 
dextercioby said:
Yes, the only requirement is that the electrons must not have the same quantum numbers. If 3 of them are identical, the 4th is forced to have different values among them.
Ok thank you. :smile:
 

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