Potassium iodide in an ascorbic acid titration with iodine solution?

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In an ascorbic acid titration with iodine solution, potassium iodide is used alongside iodine. The primary reactant in this process is iodine, not iodide. Ascorbic acid undergoes a reduction reaction during the titration. Iodine has low solubility in water but forms a soluble complex, I3-, when combined with iodide. Understanding these interactions is crucial for accurate titration results.
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When performing an ascorbic acid titration with iodine solution, iodine and potassium iodide are used. Does the potassium iodide react with the ascorbic acid as well or only the iodine?

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The reactant is either the iodine or the iodide - I'm no familiar currently. Is the ascorbic acid being reduced? Or is it being oxidized? (I should not butt-in here, since someone familiar with the analytical method would answer this more properly).
 
iodine is the reactant, not iodide. Iodine is not very soluble in water but it forms a water-soluble complex, I3-, with iodide.
 
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